Final Fantasy VII Feats - Typhon, Bahamut Fury, and a Comet

All the feats

Might as well make these an actual blog as opposed to just referencing a wayback machine link *shrugs*

Reference



First is Typhon

Reference

Featherine said:

Alright.

I see where that comes from, it depends how you want to interpret 天地崩壊 (This is Typhoon's designation/title it means "Collapsing World" or something to that effect). The main problem being 天地 / tenchi here.

Spoiler:

[LINKHL]130880[/LINKHL]

For instance, the 5th pic:
- 放たれた閃光とともに、一瞬のうちに天地が逆転し...
- hanatareta senkou to tomo ni, isshun no uchi no Tenchi ga gyatuktenshi...
- With a flash of light, the World is reversed in an instant...

So, tenchi can mean World indeed, as well as mean Heaven & Earth, Realm... It's a pretty vague term all things considered.

I'm afraid to say this because I'm sure Megatron will jump on it, but it can also mean Universe.

In fact, my dictionary says:
Heaven and Earth, Universe.
Sample sentence - 新天地を求めてアメリカへ旅立つ
Searching for a new World he left for America.

So, dunno how you want to take this.

Click to expand...

Time Frame = 0.53 seconds
Earth Radius = 6,371,000 meters

Half Circumference = PIr

Total Travel Distance = 20,015,086.8 meters
Travel Speed = 37,764,314.71 m/s
Earth Mass = 5.972 * 10^24 kilograms

KE = 0.5mv^2
m = Earth Mass
v = Travel Speed

Disintegration Yield = 4.258464388 * 10^39 joules or 1.018 tenatons

Ok

Now Bahamut Fury



As the planet Bahamut Fury starts near looks nothing like one of the planets of our Star System? It seems most likely that it traveled between star systems.

Could also make note of how the light of the star of the respective planets it flies to and from don't corroborate the star being the same, so I will.

Here, the star illuminating the planet Bahamut Fury starts near is on its left. Here, the camera starts to rotate as Bahamut Fury did some kind of 180 corkscrew so the star illuminating the planet and Bahamut Fury is now somewhere far to the right of them both. Here, Bahamut Fury starts flying into a bright light, clearly a different one than the light of the star illuminating the planet far behind itself. Here, Bahamut Fury has reached the planet Zack is on having traveled in a straight line to it, the sun clearly illuminating Fury's back and the planet. Here, we see the sun is directly behind Fury.

With how the sun of Zack's planet is in relation to the star illuminating the initial planet? There's no way they could be the same star due to how the shadows and light end up sitting upon them respectively. The initial star was directly to the right of Fury and the first planet before initializing transit. Fury traveling to Zack's planet in a straight line, we shouldn't have seen as direct an illumination of the moon and earth's back from here as we did if the planets were from the same star system.

Well, I mean, that and the fact the planet Fury started near being near enough to its host star to be so brightly illuminated at all while not looking like Mercury, Venus, or Mars? Flat out eliminated the possibility to begin with anyway.

Time Frame = 7.5 seconds
1 lightyear = 9.461 * 10^15 meters
Closest Star to Earth = 4.24 lightyears (apparently)
Total Distance = 4.011464 * 10^16 meters
Bahamut Fury Speed = 5.348618667 * 10^15 m/s or 17,828,728.89C

Next the Exaflare



This one's kind of odd

There's a molten moon dispersal of mass and a regular moon dispersal mass

So to get a rough idea of the mass I need to use for each, I need to solve for the molten mass first

Moon Diameter = 308 pixels
Molten Moon Diameter = 286 pixels
Regular Moon Remains = 177 pixels
Moon Diameter - Regular Moon Remains = Molten Moon Depth
Molten Moon Depth = 131 pixels
Molten Mass Travel = 385 pixels
Moon Expansion = 469 pixels
Molten Moon Diameter/Moon Diameter = 0.929
Molten Moon Depth/Moon Diameter = 0.425
Molten Mass Travel/Moon Diameter = 1.25
Moon Expansion/Moon Diameter = 1.523

Moon Diameter = 3,474 kilometers or 3,474,000 meters

Molten Moon Diameter = 3,227.346 kilometers
Molten Moon Depth = 1,476.45 kilometers

Moon Total Volume = 21,958,000,000 km^3

Volume = (2/3)PIr1^2r2
r1 = Molten Moon Diameter/2
r2 = Molten Moon Depth

Molten Moon Volume = 8,052,086,333 km^3

Molten Moon Volume/Moon Total Volume = 0.367

Moon Total Mass = 7.342 * 10^22 kilograms
Molten Moon Mass = 2.694514 * 10^22 kilograms
Remaining Moon Mass = 4.647486 * 10^22 kilograms

Time Frame = 1.44 seconds

Molten Mass Travel = 4,342,500 meters
Moon Expansion = 5,290,902 meters

(Moon Expansion - Moon Diameter)/2 = Remaining Moon Mass Travel

Remaining Moon Mass Travel = 908,451 meters

Molten Mass Speed = 3,015,625 m/s
Remaining Mass Speed = 630,868.75 m/s

KE = 0.5mv^2

m = Molten/Remaining Moon Mass
v = Molten/Remaining Mass Speed

Molten Mass Energy = 1.225194726 * 10^35 joules
Remaining Mass Energy = 9.249134029 * 10^33 joules

Exaflare Yield = 1.317686066 * 10^35 joules or 31.493 yottatons

Now Supernova, though since I've done an energy already? I'm just looking for a speed

Some references



Time Frame = 0.94 seconds
1 lightyear = 9.461 * 10^15 meters
Milky Way = 100,000 lightyears

Angular size basically

Panel Height = 688 pixels
Object Size 1 = 114 pixels
Object Size 2 = 237 pixels

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

Object Degree Size 1 = 13.236 degrees

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

Object Degree Size 2 = 27.122 degrees

Calculator

Number of Lightyears Away (Image 1) = 430,950 lightyears
Number of Lightyears Away (Image 2) = 207,290 lightyears

Image 1 - Image 2 = Total Distance

Total Distance = 223,660 lightyears
Total Distance = 2.11604726 * 10^21 meters

Comet Speed = 2,251,114,106,000,000,000,000 m/s or 7,503,713,688,000C

Cool