Spoiler:
All the feats
Might as well make these an actual blog as opposed to just referencing a wayback machine link *shrugs*
Reference
First is Typhon
Reference
Time Frame = 0.53 seconds
Earth Radius = 6,371,000 meters
Half Circumference = PIr
Total Travel Distance = 20,015,086.8 meters
Travel Speed = 37,764,314.71 m/s
Earth Mass = 5.972 * 10^24 kilograms
KE = 0.5mv^2
m = Earth Mass
v = Travel Speed
Disintegration Yield = 4.258464388 * 10^39 joules or 1.018 tenatons
Ok
Now Bahamut Fury
As the planet Bahamut Fury starts near looks nothing like one of the planets of our Star System? It seems most likely that it traveled between star systems.
Could also make note of how the light of the star of the respective planets it flies to and from don't corroborate the star being the same, so I will.
Here, the star illuminating the planet Bahamut Fury starts near is on its left. Here, the camera starts to rotate as Bahamut Fury did some kind of 180 corkscrew so the star illuminating the planet and Bahamut Fury is now somewhere far to the right of them both. Here, Bahamut Fury starts flying into a bright light, clearly a different one than the light of the star illuminating the planet far behind itself. Here, Bahamut Fury has reached the planet Zack is on having traveled in a straight line to it, the sun clearly illuminating Fury's back and the planet. Here, we see the sun is directly behind Fury.
With how the sun of Zack's planet is in relation to the star illuminating the initial planet? There's no way they could be the same star due to how the shadows and light end up sitting upon them respectively. The initial star was directly to the right of Fury and the first planet before initializing transit. Fury traveling to Zack's planet in a straight line, we shouldn't have seen as direct an illumination of the moon and earth's back from here as we did if the planets were from the same star system.
Well, I mean, that and the fact the planet Fury started near being near enough to its host star to be so brightly illuminated at all while not looking like Mercury, Venus, or Mars? Flat out eliminated the possibility to begin with anyway.
Time Frame = 7.5 seconds
1 lightyear = 9.461 * 10^15 meters
Closest Star to Earth = 4.24 lightyears (apparently)
Total Distance = 4.011464 * 10^16 meters
Bahamut Fury Speed = 5.348618667 * 10^15 m/s or 17,828,728.89C
Next the Exaflare
This one's kind of odd
There's a molten moon dispersal of mass and a regular moon dispersal mass
So to get a rough idea of the mass I need to use for each, I need to solve for the molten mass first
Moon Diameter = 308 pixels
Molten Moon Diameter = 286 pixels
Regular Moon Remains = 177 pixels
Moon Diameter - Regular Moon Remains = Molten Moon Depth
Molten Moon Depth = 131 pixels
Molten Mass Travel = 385 pixels
Moon Expansion = 469 pixels
Molten Moon Diameter/Moon Diameter = 0.929
Molten Moon Depth/Moon Diameter = 0.425
Molten Mass Travel/Moon Diameter = 1.25
Moon Expansion/Moon Diameter = 1.523
Moon Diameter = 3,474 kilometers or 3,474,000 meters
Molten Moon Diameter = 3,227.346 kilometers
Molten Moon Depth = 1,476.45 kilometers
Moon Total Volume = 21,958,000,000 km^3
Volume = (2/3)PIr1^2r2
r1 = Molten Moon Diameter/2
r2 = Molten Moon Depth
Molten Moon Volume = 8,052,086,333 km^3
Molten Moon Volume/Moon Total Volume = 0.367
Moon Total Mass = 7.342 * 10^22 kilograms
Molten Moon Mass = 2.694514 * 10^22 kilograms
Remaining Moon Mass = 4.647486 * 10^22 kilograms
Time Frame = 1.44 seconds
Molten Mass Travel = 4,342,500 meters
Moon Expansion = 5,290,902 meters
(Moon Expansion - Moon Diameter)/2 = Remaining Moon Mass Travel
Remaining Moon Mass Travel = 908,451 meters
Molten Mass Speed = 3,015,625 m/s
Remaining Mass Speed = 630,868.75 m/s
KE = 0.5mv^2
m = Molten/Remaining Moon Mass
v = Molten/Remaining Mass Speed
Molten Mass Energy = 1.225194726 * 10^35 joules
Remaining Mass Energy = 9.249134029 * 10^33 joules
Exaflare Yield = 1.317686066 * 10^35 joules or 31.493 yottatons
Now Supernova, though since I've done an energy already? I'm just looking for a speed
Some references
Time Frame = 0.94 seconds
1 lightyear = 9.461 * 10^15 meters
Milky Way = 100,000 lightyears
Angular size basically
Panel Height = 688 pixels
Object Size 1 = 114 pixels
Object Size 2 = 237 pixels
object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))
Object Degree Size 1 = 13.236 degrees
object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))
Object Degree Size 2 = 27.122 degrees
Calculator
Number of Lightyears Away (Image 1) = 430,950 lightyears
Number of Lightyears Away (Image 2) = 207,290 lightyears
Image 1 - Image 2 = Total Distance
Total Distance = 223,660 lightyears
Total Distance = 2.11604726 * 10^21 meters
Comet Speed = 2,251,114,106,000,000,000,000 m/s or 7,503,713,688,000C
Cool
Might as well make these an actual blog as opposed to just referencing a wayback machine link *shrugs*
Reference
Spoiler:

First is Typhon
Reference
Alright.
I see where that comes from, it depends how you want to interpret 天地崩壊 (This is Typhoon's designation/title it means "Collapsing World" or something to that effect). The main problem being 天地 / tenchi here.
Spoiler:[LINKHL]130880[/LINKHL]
For instance, the 5th pic:
- 放たれた閃光とともに、一瞬のうちに天地が逆転し...
- hanatareta senkou to tomo ni, isshun no uchi no Tenchi ga gyatuktenshi...
- With a flash of light, the World is reversed in an instant...
So, tenchi can mean World indeed, as well as mean Heaven & Earth, Realm... It's a pretty vague term all things considered.
I'm afraid to say this because I'm sure Megatron will jump on it, but it can also mean Universe.
In fact, my dictionary says:
Heaven and Earth, Universe.
Sample sentence - 新天地を求めてアメリカへ旅立つ
Searching for a new World he left for America.
So, dunno how you want to take this.
Spoiler:


Time Frame = 0.53 seconds
Earth Radius = 6,371,000 meters
Half Circumference = PIr
Total Travel Distance = 20,015,086.8 meters
Travel Speed = 37,764,314.71 m/s
Earth Mass = 5.972 * 10^24 kilograms
KE = 0.5mv^2
m = Earth Mass
v = Travel Speed
Disintegration Yield = 4.258464388 * 10^39 joules or 1.018 tenatons
Ok
Now Bahamut Fury
Spoiler:


As the planet Bahamut Fury starts near looks nothing like one of the planets of our Star System? It seems most likely that it traveled between star systems.
Could also make note of how the light of the star of the respective planets it flies to and from don't corroborate the star being the same, so I will.
Here, the star illuminating the planet Bahamut Fury starts near is on its left. Here, the camera starts to rotate as Bahamut Fury did some kind of 180 corkscrew so the star illuminating the planet and Bahamut Fury is now somewhere far to the right of them both. Here, Bahamut Fury starts flying into a bright light, clearly a different one than the light of the star illuminating the planet far behind itself. Here, Bahamut Fury has reached the planet Zack is on having traveled in a straight line to it, the sun clearly illuminating Fury's back and the planet. Here, we see the sun is directly behind Fury.
With how the sun of Zack's planet is in relation to the star illuminating the initial planet? There's no way they could be the same star due to how the shadows and light end up sitting upon them respectively. The initial star was directly to the right of Fury and the first planet before initializing transit. Fury traveling to Zack's planet in a straight line, we shouldn't have seen as direct an illumination of the moon and earth's back from here as we did if the planets were from the same star system.
Well, I mean, that and the fact the planet Fury started near being near enough to its host star to be so brightly illuminated at all while not looking like Mercury, Venus, or Mars? Flat out eliminated the possibility to begin with anyway.
Time Frame = 7.5 seconds
1 lightyear = 9.461 * 10^15 meters
Closest Star to Earth = 4.24 lightyears (apparently)
Total Distance = 4.011464 * 10^16 meters
Bahamut Fury Speed = 5.348618667 * 10^15 m/s or 17,828,728.89C
Next the Exaflare
Spoiler:


This one's kind of odd
There's a molten moon dispersal of mass and a regular moon dispersal mass
So to get a rough idea of the mass I need to use for each, I need to solve for the molten mass first
Moon Diameter = 308 pixels
Molten Moon Diameter = 286 pixels
Regular Moon Remains = 177 pixels
Moon Diameter - Regular Moon Remains = Molten Moon Depth
Molten Moon Depth = 131 pixels
Molten Mass Travel = 385 pixels
Moon Expansion = 469 pixels
Molten Moon Diameter/Moon Diameter = 0.929
Molten Moon Depth/Moon Diameter = 0.425
Molten Mass Travel/Moon Diameter = 1.25
Moon Expansion/Moon Diameter = 1.523
Moon Diameter = 3,474 kilometers or 3,474,000 meters
Molten Moon Diameter = 3,227.346 kilometers
Molten Moon Depth = 1,476.45 kilometers
Moon Total Volume = 21,958,000,000 km^3
Volume = (2/3)PIr1^2r2
r1 = Molten Moon Diameter/2
r2 = Molten Moon Depth
Molten Moon Volume = 8,052,086,333 km^3
Molten Moon Volume/Moon Total Volume = 0.367
Moon Total Mass = 7.342 * 10^22 kilograms
Molten Moon Mass = 2.694514 * 10^22 kilograms
Remaining Moon Mass = 4.647486 * 10^22 kilograms
Time Frame = 1.44 seconds
Molten Mass Travel = 4,342,500 meters
Moon Expansion = 5,290,902 meters
(Moon Expansion - Moon Diameter)/2 = Remaining Moon Mass Travel
Remaining Moon Mass Travel = 908,451 meters
Molten Mass Speed = 3,015,625 m/s
Remaining Mass Speed = 630,868.75 m/s
KE = 0.5mv^2
m = Molten/Remaining Moon Mass
v = Molten/Remaining Mass Speed
Molten Mass Energy = 1.225194726 * 10^35 joules
Remaining Mass Energy = 9.249134029 * 10^33 joules
Exaflare Yield = 1.317686066 * 10^35 joules or 31.493 yottatons
Now Supernova, though since I've done an energy already? I'm just looking for a speed
Some references
Spoiler:


Time Frame = 0.94 seconds
1 lightyear = 9.461 * 10^15 meters
Milky Way = 100,000 lightyears
Angular size basically
Panel Height = 688 pixels
Object Size 1 = 114 pixels
Object Size 2 = 237 pixels
object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))
Object Degree Size 1 = 13.236 degrees
object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))
Object Degree Size 2 = 27.122 degrees
Calculator
Number of Lightyears Away (Image 1) = 430,950 lightyears
Number of Lightyears Away (Image 2) = 207,290 lightyears
Image 1 - Image 2 = Total Distance
Total Distance = 223,660 lightyears
Total Distance = 2.11604726 * 10^21 meters
Comet Speed = 2,251,114,106,000,000,000,000 m/s or 7,503,713,688,000C
Cool
Final Tally
Disintegration Yield = 1.018 tenatons
Bahamut Fury's Speed = 17,828,728.89C
Exaflare Yield = 31.493 yottatons
Supernova Comet Telekinesis Speed = 7,503,713,688,000C